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To correct this, you can no longer refer to the singleton instance property, but instead use an instance of the Manager class instead:
| Code Block | ||||
|---|---|---|---|---|
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var manager = new JiwaFinancials.Jiwa.JiwaApplication.Manager();
manager.Logon("MyServer", "JiwaDemo", JiwaFinancials.Jiwa.JiwaODBC.database.AuthenticationModes.JiwaAuthentication, "Admin", password);
manager.BusinessLogicFactory.CreateBusinessLogic<JiwaFinancials.Jiwa.JiwaSales.SalesOrder.SalesOrder>()null;
var db = manager.Database;
using (SqlCommand SQLCmd = new SqlCommand(sql, db.SQLConnection, db.SQLTransaction))
{
} |
...
An example of using the Entity Factory of the Manager:
| Code Block | ||||
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var branch = Manager.EntityFactory.CreateEntity<JiwaFinancials.Jiwa.JiwaApplication.Entities.Sales.Branch>();
branch.ReadRecord("ABC123"); |
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